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=1900R-R^2
We move all terms to the left:
-(1900R-R^2)=0
We get rid of parentheses
R^2-1900R=0
a = 1; b = -1900; c = 0;
Δ = b2-4ac
Δ = -19002-4·1·0
Δ = 3610000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3610000}=1900$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1900)-1900}{2*1}=\frac{0}{2} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1900)+1900}{2*1}=\frac{3800}{2} =1900 $
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